fix(main): use package name instead of __main__.py in usage output

fire/__main__.py

@@ -50,14 +50,20 @@ def import_from_file_path(path):
 
   Returns:
     Tuple[ModuleType, str]: returns the imported module and the module name,
-      usually extracted from the path itself.
+      usually extracted from the path itself. If the file is __main__.py, the
+      package name (parent directory) is used instead.
   """
 
   if not os.path.exists(path):
     raise OSError('Given file path does not exist.')
 
   module_name = os.path.basename(path)
 
+  # If the file is __main__.py, use the parent directory name as the module name
+  # This fixes the issue where "python -m mypackage" shows "__main__.py" in usage
+  if module_name == '__main__.py':
+    module_name = os.path.basename(os.path.dirname(path))
+
   spec = util.spec_from_file_location(module_name, path)
 
   if spec is None or spec.loader is None:

fire/core.py

@@ -105,6 +105,10 @@ def Fire(component=None, command=None, name=None, serialize=None):
   """
   name = name or os.path.basename(sys.argv[0])
 
+  # If the script name is __main__.py (python -m package), use the package name instead
+  if name == '__main__.py':
+    name = os.path.basename(os.path.dirname(sys.argv[0]))
+
   # Get args as a list.
   if isinstance(command, str):
     args = shlex.split(command)